Friday, March 27, 2009

7.9 Due March 27

The thing I mostly found difficult was seeing how any permutation can be written as the product of disjoint cycles, but then it made sense when I thought of how you could just see it as different move made on the identity permutation.

I think this is neat information and I wonder where it is applied the most. I wonder what kind of subgroups you could make somehow using the disjoint factorization of permutations.

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